Using Gibb's free energy change,∆G° = 57.34 kj mol-1, for the reaction, X2 Y(s) \(\rightleftharpoons \) 2X+ + Y2-(aq) calculate the solubility product of X2Y in water at 300 K
(R = 8.3JK-1 Mol-1)
10-10
10-12
10-14
can not be calculated from the given data