Choose the correct or the most suitable answer from the given four alternatives.
If, \(y=a+b{ x }^{ 2 }\) where a, b are arbitrary constants, then
\(\frac { d^{ 2 }y }{ d{ x }^{ 2 } } =2xy\)
\(x\frac { d^{ 2 }y }{ d{ x }^{ 2 } } ={ y }_{ 1 }\)
\(x\frac { d^{ 2 }y }{ d{ x }^{ 2 } } -\frac { dy }{ dx } +y=0\)
\(x\frac { d^{ 2 }y }{ d{ x }^{ 2 } } =2xy\)